Let m=6x+5. Which equation is equivalent to (6x+5)^(2)-10=-18 x-15 in terms of m ? Choose 1 answer: (A) m^(2)-3m+5=0 (B) m^(2)+3m+5=0 (C) m^(2)-3m-10=0 (D) m^(2)+3m-10=0

Substitute m for 6x+5: Substitute m for 6x+5 in the given equation. (6x+5)^(2)-10=-18x-15 becomes m^2-10=-18x-15.Replace -18x with -3m: Since m=6x+5, we can replace -18x with -3m by dividing the coefficient of x in m (which is 6) into -18 to get -3. m^2-10=-3m-15.Add 3m to both sides: Add 3m to both sides of the equation to get all terms involving m on one side. m^2-10+3m=-15.Add 15 to isolate: Add 15 to both sides of the equation to isolate the quadratic expression on one side. m^2+3m-10=0.Match with answer choices: Match the resulting equation with the answer choices. The equation m^2+3m-10=0 corresponds to answer choice (C).

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Q. Let

m=6 x+5

\newline

Which equation is equivalent to

(6 x+5)^{2}-10=-18 x-15

in terms of

m

\newline

Choose

1

answer:

\newline

(A)

m^{2}-3 m+5=0

\newline

(B)

m^{2}+3 m+5=0

\newline

(C)

m^{2}-3 m-10=0

\newline

(D)

m^{2}+3 m-10=0

Substitute $m$ for $6x+5$ : Substitute $m$ for $6x+5$ in the given equation. $\newline$ $(6x+5)^{2}-10=-18x-15$ becomes $m^{2}-10=-18x-15$ .
Replace $-18x$ with $-3m$ : Since $m=6x+5$ , we can replace $-18x$ with $-3m$ by dividing the coefficient of $x$ in $m$ (which is $6$ ) into $-18$ to get $-3$ . $\newline$ $-3m$ $0$ .
Add $3m$ to both sides: Add $3m$ to both sides of the equation to get all terms involving $m$ on one side. $\newline$ $m^2-10+3m=-15$ .
Add $15$ to isolate: Add $15$ to both sides of the equation to isolate the quadratic expression on one side. $\newline$ $m^2+3m-10=0$ .
Match with answer choices: Match the resulting equation with the answer choices. $\newline$ The equation $m^2+3m-10=0$ corresponds to answer choice $(C)$ .