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Last Saturday, Erin and Krysta each biked the Prairie Point Trail, a 2020-mile path leading to the peak of Prairie Point Mountain. Both girls started at 7:007:00 A.M., heading toward the peak. Erin started at the trailhead and biked at a constant speed of 1010 miles per hour. Krysta started at an entry point 33 miles ahead of the trailhead and rode at a steady pace of 88 miles per hour. If each girl kept a constant speed, which equation can you use to find hh, the number of hours it took for Erin to catch up to Krysta?\newlineChoices:\newline(A) 10=3h+810 = 3h + 8\newline(B) 10h=8h+310h = 8h + 3\newlineHow long did it take for Erin to catch up to Krysta?\newlineSimplify any fractions.\newline___\_\_\_ hours\newline

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Q. Last Saturday, Erin and Krysta each biked the Prairie Point Trail, a 2020-mile path leading to the peak of Prairie Point Mountain. Both girls started at 7:007:00 A.M., heading toward the peak. Erin started at the trailhead and biked at a constant speed of 1010 miles per hour. Krysta started at an entry point 33 miles ahead of the trailhead and rode at a steady pace of 88 miles per hour. If each girl kept a constant speed, which equation can you use to find hh, the number of hours it took for Erin to catch up to Krysta?\newlineChoices:\newline(A) 10=3h+810 = 3h + 8\newline(B) 10h=8h+310h = 8h + 3\newlineHow long did it take for Erin to catch up to Krysta?\newlineSimplify any fractions.\newline___\_\_\_ hours\newline
  1. Set Up Problem: Let's set up the problem. Erin starts 33 miles behind Krysta and is biking at a faster speed. We want to find out when the distance Erin has biked equals the distance Krysta has biked. Since Krysta has a 33-mile head start, we need to add this to the distance she travels at her speed of 88 miles per hour. Erin's distance will be her speed (1010 miles per hour) times the number of hours, hh. The equation will set these two expressions equal to each other to find when Erin catches up to Krysta.
  2. Write Equation for Erin: We can write the equation for the distance Erin travels as 10h10h, since she travels at 1010 miles per hour for hh hours. For Krysta, we add her head start of 33 miles to the distance she travels at 88 miles per hour for hh hours, which gives us 8h+38h + 3. Setting these equal to each other gives us the equation 10h=8h+310h = 8h + 3.
  3. Solve Equation for h: Now we solve the equation 10h=8h+310h = 8h + 3 for hh. We subtract 8h8h from both sides to isolate the variable hh on one side of the equation.\newline10h8h=8h+38h10h - 8h = 8h + 3 - 8h\newlineThis simplifies to:\newline2h=32h = 3
  4. Find Value of h: To find the value of h, we divide both sides of the equation by 22. \newline2h2=32\frac{2h}{2} = \frac{3}{2}\newlineThis gives us:\newlineh=32h = \frac{3}{2}
  5. Calculate Time Taken: We simplify the fraction 32\frac{3}{2} to get the number of hours it took Erin to catch up to Krysta.\newline32=1.5\frac{3}{2} = 1.5\newlineSo, it took Erin 1.51.5 hours to catch up to Krysta.

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