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Kofi tried to solve the differential equation $\frac{d y}{d x}=3 x^{-2} e^{-y}$. This is his work:$\newline$$$\frac{d y}{d x}=3 x^{-2} e^{-y}$$$\newline$Step $1$: $\quad \int e^{y} d y=\int 3 x^{-2} d x$$\newline$Step $2$: $\quad e^{y}=-\frac{3}{x}$$\newline$Step $3$: $\quad \ln \left(e^{y}\right)=\ln \left(-\frac{3}{x}\right)$$\newline$Step $4$: $\quad y=\ln \left(-\frac{3}{x}\right)+C$$\newline$Is Kofi's work correct? If not, what is his mistake?$\newline$Choose $1$ answer:$\newline$(A) Kofi's work is correct.$\newline$(B) Step $1$ is incorrect. The separation of variables wasn't done correctly.$\newline$(C) Step $2$ is incorrect. The right-hand side of the equation should be $-\frac{3}{x}+C$.$\newline$(D) Step $3$ is incorrect. Kofi should not have a negative symbol inside of a natural logarithm.