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Jaxon is organizing textbooks on his bookshelf. He has an English textbook, a biology textbook, a physics textbook, and a writing textbook. How many different ways can he line the textbooks up on his bookshelf?
Answer:

Jaxon is organizing textbooks on his bookshelf. He has an English textbook, a biology textbook, a physics textbook, and a writing textbook. How many different ways can he line the textbooks up on his bookshelf? $\newline$ Answer:

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Unit prices with unit conversions

Full solution

Q. Jaxon is organizing textbooks on his bookshelf. He has an English textbook, a biology textbook, a physics textbook, and a writing textbook. How many different ways can he line the textbooks up on his bookshelf?

\newline

Answer:

Identify the problem: Identify the problem. $\newline$ We need to find the number of different arrangements for the $4$ textbooks.
Use factorial concept: Use the factorial concept for arrangements. $\newline$ The number of ways to arrange $n$ items is $n!$ ( $n$ factorial), which is the product of all positive integers up to $n$ .
Calculate factorial of $4$ : Calculate the factorial of $4$ . $\newline$ $4! = 4 \times 3 \times 2 \times 1 = 24$
Verify the calculation: Verify the calculation. $\newline$ Recheck the multiplication: $4 \times 3 = 12$ , $12 \times 2 = 24$ , $24 \times 1 = 24$ . The calculation is correct.

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