Jack needs to hire someone to feed and walk his dogs while he is away on a business trip. His neighbor said that she can do it for $40 per day. He also found a pet-sitting company that charges $25 per day, plus a $75 registration fee. Which equation can you use to find d, the number of days the trip would need to last for the two options to cost the same? Choices: (A)40d + 25 = 75d (B)40d = 25d + 75 How many days would the trip need to last for the two options to cost the same? ____ days

Question

Jack needs to hire someone to feed and walk his dogs while he is away on a business trip. His neighbor said that she can do it for $40 per day. He also found a pet-sitting company that charges $25 per day, plus a $75 registration fee. Which equation can you use to find d, the number of days the trip would need to last for the two options to cost the same?   Choices: (A)40d + 25 = 75d (B)40d = 25d + 75  How many days would the trip need to last for the two options to cost the same?   ____ days

Bytelearn · Accepted Answer

Set up equation:  First, let's set up the equation to find when both options cost the same. The neighbor charges $40 per day, so for d days, it's 40d dollars. The pet-sitting company charges $25 per day plus a $75 registration fee, so for d days, it's 25d + 75 dollars. Set these equal to find d: 40d = 25d + 75. Isolate terms with d:  Now, solve for d. Subtract 25d from both sides to isolate the terms with d on one side: 40d - 25d = 75. Simplify equation:  Simplify the equation: 15d = 75. Divide to solve for d:  Divide both sides by 15 to solve for d: d = 75 / 15. Calculate d:  Calculate d: 75 divided by 15 equals 5. So, d = 5.

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