In which direction does the parabola y + 4x^2 = -4 open? Choices: (A)up (B)down (C)right (D)left

Identify Parabola Type: y + 4x^2 = -4 Identify if the parabola is vertical or horizontal. Since the x term is squared, it's a vertical parabola.Isolate y in Standard Form: y + 4x^2 = -4 Isolate y to get it into standard form. y = -4x^2 - 4Determine Parabola Direction: y = -4x^2 - 4 Determine the direction the parabola opens. The coefficient of x^2 is -4, so a = -4. Since a < 0, the parabola opens downwards.

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In which direction does the parabola $y + 4x^2 = -4$ open? $\newline$ Choices: $\newline$ (A) up $\newline$ (B) down $\newline$ (C) right $\newline$ (D) left

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Algebra 2

Find properties of a parabola from equations in general form

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Q. In which direction does the parabola

y + 4x^2 = -4

open?

\newline

Choices:

\newline

(A) up

\newline

(B) down

\newline

\newline

(D) left

Identify Parabola Type: $y + 4x^2 = -4$ $\newline$ Identify if the parabola is vertical or horizontal. $\newline$ Since the $x$ term is squared, it's a vertical parabola.
Isolate $y$ in Standard Form: $y + 4x^2 = -4$ $\newline$ Isolate $y$ to get it into standard form. $\newline$ $y = -4x^2 - 4$
Determine Parabola Direction: $y = -4x^2 - 4$ $\newline$ Determine the direction the parabola opens. $\newline$ The coefficient of $x^2$ is $-4$ , so $a = -4$ . $\newline$ Since a < 0, the parabola opens downwards.