In which direction does the parabola y + 4x^2 = 0 open? Choices: (A)up (B)down (C)right (D)left

Rewrite Equation: Now, let's rewrite the equation to see the standard form of the parabola. Subtract y from both sides to isolate the 4x^2 term. y + 4x^2 - y = 0 - y 4x^2 = -yDivide by 4: Next, we divide by 4 to get x^2 on its own. 4x^2 / 4 = -y / 4 x^2 = -y / 4Coefficient Analysis: Now we look at the coefficient of x^2, which is 1. Since the coefficient is positive, the parabola opens upwards.

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In which direction does the parabola $y + 4x^2 = 0$ open? $\newline$ Choices: $\newline$ (A)up $\newline$ (B)down $\newline$ (C)right $\newline$ (D)left

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Algebra 2

Find properties of a parabola from equations in general form

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Q. In which direction does the parabola

y + 4x^2 = 0

open?

\newline

Choices:

\newline

(A)up

\newline

(B)down

\newline

(C)right

\newline

(D)left

Rewrite Equation: Now, let's rewrite the equation to see the standard form of the parabola. $\newline$ Subtract $y$ from both sides to isolate the $4x^2$ term. $\newline$ $y + 4x^2 - y = 0 - y$ $\newline$ $4x^2 = -y$
Divide by $4$ : Next, we divide by $4$ to get $x^2$ on its own. $\newline$ $4x^2 / 4 = -y / 4$ $\newline$ $x^2 = -y / 4$
Coefficient Analysis: Now we look at the coefficient of $x^2$ , which is $1$ . Since the coefficient is positive, the parabola opens upwards.