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In which direction does the parabola y−10x2=5y - 10x^2 = 5 open?\newlineChoices:\newline(A) up\newline(B) down\newline(C) right\newline(D) left

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Q. In which direction does the parabola y−10x2=5y - 10x^2 = 5 open?\newlineChoices:\newline(A) up\newline(B) down\newline(C) right\newline(D) left
  1. Isolate y: Now, let's get the equation into standard form by isolating y.\newlineAdd 10x210x^2 to both sides to get y on one side.\newliney−10x2+10x2=5+10x2y - 10x^2 + 10x^2 = 5 + 10x^2\newliney=10x2+5y = 10x^2 + 5
  2. Determine parabola direction: Next, we determine the direction the parabola opens by looking at the coefficient of x2x^2. The coefficient of x2x^2 is 1010, so a=10a = 10. Since a > 0, the parabola opens upwards.

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