In which direction does the parabola x - 3y^2 = -4 open? Choices: (A)up (B)down (C)right (D)left

Identify Parabola Orientation: Identify if the parabola is vertical or horizontal. x - 3y^2 = -4 has a squared y term, so it's horizontal.Rearrange Equation to Standard Form: Rearrange the equation to standard form by isolating x. x - 3y^2 + 3y^2 = -4 + 3y^2 x = 3y^2 - 4Determine Parabola Opening Direction: Determine the direction of the parabola opening. The coefficient of y^2 is 3, so a = 3. Since a > 0, the parabola opens to the right.

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In which direction does the parabola $x - 3y^2 = -4$ open? $\newline$ Choices: $\newline$ (A)up $\newline$ (B)down $\newline$ (C)right $\newline$ (D)left

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Algebra 2

Find properties of a parabola from equations in general form

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Q. In which direction does the parabola

x - 3y^2 = -4

open?

\newline

Choices:

\newline

(A)up

\newline

(B)down

\newline

(C)right

\newline

(D)left

Identify Parabola Orientation: Identify if the parabola is vertical or horizontal. $x - 3y^2 = -4$ has a squared $y$ term, so it's horizontal.
Rearrange Equation to Standard Form: Rearrange the equation to standard form by isolating $x$ . $x - 3y^2 + 3y^2 = -4 + 3y^2$ $x = 3y^2 - 4$
Determine Parabola Opening Direction: Determine the direction of the parabola opening. The coefficient of $y^2$ is $3$ , so $a = 3$ . Since a > 0, the parabola opens to the right.