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In the summertime, Rick likes to buy cherries at the farmers market. On his first visit of the season, he bought 2142\frac{1}{4} pounds of cherries. On his next visit, he bought 3123\frac{1}{2} pounds of cherries and used a coupon to get $7\$7 off his purchase. He noticed that he was charged the same amount each time.\newlineWhich equation can you use to find pp, the price of a pound of cherries?\newlineChoices:\newline(A)2.25p=3.5+7p2.25p = 3.5 + 7p\newline(B)2.25p=3.5p72.25p = 3.5p - 7\newlineWhat is the price of a pound of cherries?\newline____ $\$

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Q. In the summertime, Rick likes to buy cherries at the farmers market. On his first visit of the season, he bought 2142\frac{1}{4} pounds of cherries. On his next visit, he bought 3123\frac{1}{2} pounds of cherries and used a coupon to get $7\$7 off his purchase. He noticed that he was charged the same amount each time.\newlineWhich equation can you use to find pp, the price of a pound of cherries?\newlineChoices:\newline(A)2.25p=3.5+7p2.25p = 3.5 + 7p\newline(B)2.25p=3.5p72.25p = 3.5p - 7\newlineWhat is the price of a pound of cherries?\newline____ $\$
  1. Understand the problem: Understand the problem.\newlineRick bought 2142\frac{1}{4} pounds of cherries on his first visit and 3123\frac{1}{2} pounds on his second visit. He used a $7\$7 coupon on the second visit. He was charged the same total amount on both visits. We need to find the price per pound of cherries, denoted as pp.
  2. Convert to improper fractions: Convert mixed numbers to improper fractions to make calculations easier.\newline2142 \frac{1}{4} pounds = (2×4+1)/4=94(2 \times 4 + 1)/4 = \frac{9}{4} pounds\newline3123 \frac{1}{2} pounds = (3×2+1)/2=72(3 \times 2 + 1)/2 = \frac{7}{2} pounds
  3. Set up the equation: Set up the equation based on the information given.\newlineSince Rick was charged the same amount each time, the cost for the first visit 94\frac{9}{4} pounds at pp dollars per pound) should equal the cost for the second visit (72\frac{7}{2} pounds at pp dollars per pound minus the $7\$7 coupon).\newline94p=72p7\frac{9}{4}p = \frac{7}{2}p - 7
  4. Identify correct equation: Identify the correct equation from the choices given.\newlineThe correct equation that represents the situation is (B) 2.25p=3.5p72.25p = 3.5p - 7, which is the same as the equation we derived in Step 33 after converting the mixed numbers to decimals.
  5. Solve for p: Solve the equation for p.\newline2.25p=3.5p72.25p = 3.5p - 7\newlineSubtract 2.25p2.25p from both sides to get:\newline0=1.25p70 = 1.25p - 7\newlineAdd 77 to both sides to get:\newline7=1.25p7 = 1.25p\newlineDivide both sides by 1.251.25 to get:\newlinep=71.25p = \frac{7}{1.25}\newlinep=5.6p = 5.6

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