Q. In the data set below, what is the variance?9,3,3,4,5If the answer is a decimal, round it to the nearest tenth.variance (σ2): _____
Data Set: Data set: 9,3,3,4,5Mean μ=4.8Calculate the sum of the squared differences from the mean, Σ(xi−μ)2.(9−4.8)2+(3−4.8)2+(3−4.8)2+(4−4.8)2+(5−4.8)2=(4.2)2+(−1.8)2+(−1.8)2+(−0.8)2+(0.2)2=17.64+3.24+3.24+0.64+0.04$= \(24\).\(8\)
Calculate Sum: We have the sum of squared differences \(\Sigma(x_i - \mu)^2 = 24.8\) and the number of data points \(N = 5\). Now, calculate the variance \(\sigma^2\). \(\sigma^2 = (\Sigma(x_i - \mu)^2)/N\) \(\sigma^2 = 24.8/5\) \(\sigma^2 = 4.96\) Round the variance to the nearest tenth. \(\sigma^2 \approx 5.0\)
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