In the data set below, what is the variance? 9, 1, 8, 5, 2 If the answer is a decimal, round it to the nearest tenth. variance (σ^2): _____

Calculate Mean: Calculate the mean of the data set. Mean = (9 + 1 + 8 + 5 + 2)/5 μ = 25/5 μ = 5Sum of Squared Differences: Data set: 9, 1, 8, 5, 2 μ = 5 Calculate the sum of the squared differences from the mean. (9 - 5)^2 + (1 - 5)^2 + (8 - 5)^2 + (5 - 5)^2 + (2 - 5)^2 = (4)^2 + (-4)^2 + (3)^2 + (0)^2 + (-3)^2 = 16 + 16 + 9 + 0 + 9 = 50Variance Calculation: We have the sum of the squared differences: Σ(x_i - μ)^2= 50 There are N= 5 data points. Calculate the variance and round your answer to the nearest tenth. σ^2 = (Σ(x_i - μ)^2)/N σ^2 = 50/5 σ^2 = 10 Since the result is a whole number, there is no need to round to the nearest tenth.

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In the data set below, what is the variance? $\newline$ $9, 1, 8, 5, 2$ $\newline$ If the answer is a decimal, round it to the nearest tenth. $\newline$ variance $\sigma^2$ : _____

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Algebra 1

Variance and standard deviation

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Q. In the data set below, what is the variance?

\newline

9, 1, 8, 5, 2

\newline

If the answer is a decimal, round it to the nearest tenth.

\newline

variance

\sigma^2

: _____

Calculate Mean: Calculate the mean of the data set. $\newline$ Mean = $(9 + 1 + 8 + 5 + 2)/5$ $\newline$ $\mu = 25/5$ $\newline$ $\mu = 5$
Sum of Squared Differences: Data set: $9, 1, 8, 5, 2$ $\newline$ $\mu = 5$ $\newline$ Calculate the sum of the squared differences from the mean. $\newline$ $(9 - 5)^2 + (1 - 5)^2 + (8 - 5)^2 + (5 - 5)^2 + (2 - 5)^2$ $\newline$ $= (4)^2 + (-4)^2 + (3)^2 + (0)^2 + (-3)^2$ $\newline$ $= 16 + 16 + 9 + 0 + 9$ $\newline$ $= 50$
Variance Calculation: We have the sum of the squared differences: $\newline$ $\Sigma(x_i - \mu)^2= 50$ $\newline$ There are $N= 5$ data points. $\newline$ Calculate the variance and round your answer to the nearest tenth. $\newline$ $\sigma^2 = (\Sigma(x_i - \mu)^2)/N$ $\newline$ $\sigma^2 = 50/5$ $\newline$ $\sigma^2 = 10$ $\newline$ Since the result is a whole number, there is no need to round to the nearest tenth.