In the data set below, what is the variance? 7, 9, 8, 8, 5 If the answer is a decimal, round it to the nearest tenth. variance (σ^2): _____

Calculate Variance: question_prompt: Calculate the variance for the data set 7, 9, 8, 8, 5. Subtract and Square: Now, subtract the mean from each data point and square the result. (7 - 7.4)^2 = (-0.4)^2 = 0.16 (9 - 7.4)^2 = (1.6)^2 = 2.56 (8 - 7.4)^2 = (0.6)^2 = 0.36 (8 - 7.4)^2 = (0.6)^2 = 0.36 (5 - 7.4)^2 = (-2.4)^2 = 5.76Add Squared Differences: Add up all the squared differences. Sum of squared differences = 0.16 + 2.56 + 0.36 + 0.36 + 5.76 Sum of squared differences = 9.2Divide for Variance: Divide the sum of squared differences by the number of data points to get the variance. Variance (σ^2) = 9.2 / 5 Variance (σ^2) = 1.84 Round to the nearest tenth. Variance (σ^2) ≈ 1.8

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In the data set below, what is the variance? $\newline$ $7, 9, 8, 8, 5$ $\newline$ If the answer is a decimal, round it to the nearest tenth. $\newline$ variance $(\sigma^2)$ : _____

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Algebra 1

Variance and standard deviation

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Q. In the data set below, what is the variance?

\newline

7, 9, 8, 8, 5

\newline

If the answer is a decimal, round it to the nearest tenth.

\newline

variance

(\sigma^2)

: _____

Calculate Variance: question_prompt: Calculate the variance for the data set $7, 9, 8, 8, 5$ .
Subtract and Square: Now, subtract the mean from each data point and square the result. $\newline$ $(7 - 7.4)^2 = (-0.4)^2 = 0.16$ $\newline$ $(9 - 7.4)^2 = (1.6)^2 = 2.56$ $\newline$ $(8 - 7.4)^2 = (0.6)^2 = 0.36$ $\newline$ $(8 - 7.4)^2 = (0.6)^2 = 0.36$ $\newline$ $(5 - 7.4)^2 = (-2.4)^2 = 5.76$
Add Squared Differences: Add up all the squared differences. $\newline$ Sum of squared differences = $0.16 + 2.56 + 0.36 + 0.36 + 5.76$ $\newline$ Sum of squared differences = $9.2$
Divide for Variance: Divide the sum of squared differences by the number of data points to get the variance. $\newline$ Variance $\sigma^2$ = $\frac{9.2}{5}$ $\newline$ Variance $\sigma^2$ = $1$ . $84$ $\newline$ Round to the nearest tenth. $\newline$ Variance $\sigma^2$ $\approx 1.8$