In the data set below, what is the variance? 6, 4, 6, 1, 9 If the answer is a decimal, round it to the nearest tenth. variance (σ^2): _____

Calculate Mean: Calculate the mean of the data set. Mean = (6 + 4 + 6 + 1 + 9)/5 μ = 26/5 μ = 5.2Calculate Sum of Squared Differences: Data set: 6, 4, 6, 1, 9 μ = 5.2 Calculate the sum of the squared differences from the mean. (6 - 5.2)^2 + (4 - 5.2)^2 + (6 - 5.2)^2 + (1 - 5.2)^2 + (9 - 5.2)^2 = (0.8)^2 + (-1.2)^2 + (0.8)^2 + (-4.2)^2 + (3.8)^2 = 0.64 + 1.44 + 0.64 + 17.64 + 14.44 = 34.8Calculate Variance: We know: Σ(x_i - μ)^2= 34.8 N= 5 Calculate the variance and round your answer to the nearest tenth. σ^2 = (Σ(x_i - μ)^2)/N σ^2 = 34.8/5 σ^2 = 6.96 σ^2 ≈ 7.0

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In the data set below, what is the variance? $\newline$ $6, 4, 6, 1, 9$ $\newline$ If the answer is a decimal, round it to the nearest tenth. $\newline$ variance $(\sigma^2)$ : _____

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Algebra 1

Variance and standard deviation

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Q. In the data set below, what is the variance?

\newline

6, 4, 6, 1, 9

\newline

If the answer is a decimal, round it to the nearest tenth.

\newline

variance

(\sigma^2)

: _____

Calculate Mean: Calculate the mean of the data set. $\newline$ Mean = $(6 + 4 + 6 + 1 + 9)/5$ $\newline$ $\mu = 26/5$ $\newline$ $\mu = 5.2$
Calculate Sum of Squared Differences: Data set: $6, 4, 6, 1, 9$ $\newline$ $\mu = 5.2$ $\newline$ Calculate the sum of the squared differences from the mean. $\newline$ $(6 - 5.2)^2 + (4 - 5.2)^2 + (6 - 5.2)^2 + (1 - 5.2)^2 + (9 - 5.2)^2$ $\newline$ $= (0.8)^2 + (-1.2)^2 + (0.8)^2 + (-4.2)^2 + (3.8)^2$ $\newline$ $= 0.64 + 1.44 + 0.64 + 17.64 + 14.44$ $\newline$ $= 34.8$
Calculate Variance: We know: $\newline$ $\Sigma(x_i - \mu)^2= 34.8$ $\newline$ $N= 5$ $\newline$ Calculate the variance and round your answer to the nearest tenth. $\newline$ $\sigma^2 = \frac{\Sigma(x_i - \mu)^2}{N}$ $\newline$ $\sigma^2 = \frac{34.8}{5}$ $\newline$ $\sigma^2 = 6.96$ $\newline$ $\sigma^2 \approx 7.0$