In the data set below, what is the variance? 2, 7, 1, 2, 5, 4 If the answer is a decimal, round it to the nearest tenth. variance (σ^2): _____

Data Set: Data set: 2, 7, 1, 2, 5, 4 Mean μ = 3.5 Calculate the sum of the squared deviations from the mean Σ(x_i - μ)^2. (2 - 3.5)^2 + (7 - 3.5)^2 + (1 - 3.5)^2 + (2 - 3.5)^2 + (5 - 3.5)^2 + (4 - 3.5)^2 = (-1.5)^2 + (3.5)^2 + (-2.5)^2 + (-1.5)^2 + (1.5)^2 + (0.5)^2 = 2.25 + 12.25 + 6.25 + 2.25 + 2.25 + 0.25 = 25.5Calculate Sum of Squared Deviations: We have: Σ(x_i - μ)^2= 25.5 Number of data points N= 6 Calculate the variance σ^2 and round your answer to the nearest tenth. σ^2 = (Σ(x_i - μ)^2)/N σ^2 = 25.5/6 σ^2 = 4.25 Since we need to round to the nearest tenth, σ^2 ≈ 4.3

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In the data set below, what is the variance? $\newline$ $2, 7, 1, 2, 5, 4$ $\newline$ If the answer is a decimal, round it to the nearest tenth. $\newline$ variance $(\sigma^2)$ : _____

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Algebra 1

Variance and standard deviation

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Q. In the data set below, what is the variance?

\newline

2, 7, 1, 2, 5, 4

\newline

If the answer is a decimal, round it to the nearest tenth.

\newline

variance

(\sigma^2)

: _____

Data Set: Data set: $2, 7, 1, 2, 5, 4$ $\newline$ Mean $\mu = 3.5$ $\newline$ Calculate the sum of the squared deviations from the mean $\Sigma(x_i - \mu)^2$ . $\newline$ $(2 - 3.5)^2 + (7 - 3.5)^2 + (1 - 3.5)^2 + (2 - 3.5)^2 + (5 - 3.5)^2 + (4 - 3.5)^2$ $\newline$ $= (-1.5)^2 + (3.5)^2 + (-2.5)^2 + (-1.5)^2 + (1.5)^2 + (0.5)^2$ $\newline$ $= 2.25 + 12.25 + 6.25 + 2.25 + 2.25 + 0.25$ $\newline$ $= $25$.$5$
Calculate Sum of Squared Deviations: We have:$\newline$$\Sigma(x_i - \mu)^2= 25.5$$\newline$Number of data points $N= 6$$\newline$Calculate the variance $\sigma^2$ and round your answer to the nearest tenth.$\newline$$\sigma^2 = (\Sigma(x_i - \mu)^2)/N$$\newline$$\sigma^2 = 25.5/6$$\newline$$\sigma^2 = 4.25$$\newline$Since we need to round to the nearest tenth, $\sigma^2 \approx 4.3$