In the data set below, what are the lower quartile, the median, and the upper quartile? 3, 4, 4, 6, 6, 8, 8, 9, 9, 9 lower quartile = _____ median = _____ upper quartile = _____

Question Prompt: Question prompt: Determine the lower quartile, median, and upper quartile of the given data set.Find Median: Arrange the data set in ascending order and find the median. The data set is already in ascending order: 3, 4, 4, 6, 6, 8, 8, 9, 9, 9. Since there are 10 numbers, the median will be the average of the 5th and 6th numbers. Median = (6 + 6) / 2 = 12 / 2 = 6.Lower Quartile Data: Identify the data set for the lower quartile. For the lower quartile, consider the first half of the data set, excluding the median if it is part of the data. First half is 3, 4, 4, 6, 6. Lower quartile data: 3, 4, 4, 6, 6.Find Lower Quartile: Find the value of the lower quartile. Since there are 5 numbers in the lower half, the lower quartile will be the middle number. Lower quartile = 4.Upper Quartile Data: Identify the data set for the upper quartile. For the upper quartile, consider the second half of the data set, excluding the median if it is part of the data. Second half is 8, 8, 9, 9, 9. Upper quartile data: 8, 8, 9, 9, 9.Find Upper Quartile: Find the value of the upper quartile. Since there are 5 numbers in the upper half, the upper quartile will be the middle number. Upper quartile = 9.

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In the data set below, what are the lower quartile, the median, and the upper quartile? $\newline$ $3, 4, 4, 6, 6, 8, 8, 9, 9, 9$ $\newline$ lower quartile $=$ $\_\_$ $\newline$ median $=$ $\_\_$ $\newline$ upper quartile $=$ $\_\_$

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Algebra 1

Calculate quartiles and interquartile range

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Q. In the data set below, what are the lower quartile, the median, and the upper quartile?

\newline

3, 4, 4, 6, 6, 8, 8, 9, 9, 9

\newline

lower quartile

=

\_\_

\newline

median

=

\_\_

\newline

upper quartile

=

\_\_

Question Prompt: Question prompt: Determine the lower quartile, median, and upper quartile of the given data set.
Find Median: Arrange the data set in ascending order and find the median. $\newline$ The data set is already in ascending order: $3, 4, 4, 6, 6, 8, 8, 9, 9, 9$ . $\newline$ Since there are $10$ numbers, the median will be the average of the $5$ th and $6$ th numbers. $\newline$ Median $= (6 + 6) / 2 = 12 / 2 = 6$ .
Lower Quartile Data: Identify the data set for the lower quartile. $\newline$ For the lower quartile, consider the first half of the data set, excluding the median if it is part of the data. $\newline$ First half is $3, 4, 4, 6, 6$ . $\newline$ Lower quartile data: $3, 4, 4, 6, 6$ .
Find Lower Quartile: Find the value of the lower quartile. $\newline$ Since there are $5$ numbers in the lower half, the lower quartile will be the middle number. $\newline$ Lower quartile $= 4$ .
Upper Quartile Data: Identify the data set for the upper quartile. $\newline$ For the upper quartile, consider the second half of the data set, excluding the median if it is part of the data. $\newline$ Second half is $8, 8, 9, 9, 9$ . $\newline$ Upper quartile data: $8, 8, 9, 9, 9$ .
Find Upper Quartile: Find the value of the upper quartile. $\newline$ Since there are $5$ numbers in the upper half, the upper quartile will be the middle number. $\newline$ Upper quartile $= 9$ .