In the data set below, what are the lower quartile, the median, and the upper quartile? 1, 1, 1, 1, 1, 3, 3, 3, 4, 6 lower quartile = _____ median = _____ upper quartile = _____

Arrange and Find Median: Arrange the data set in ascending order and find the median. The data set is already in ascending order: 1, 1, 1, 1, 1, 3, 3, 3, 4, 6. Since there are 10 numbers, the median will be the average of the 5th and 6th numbers. Median: (1 + 3) / 2 = 4 / 2 = 2.Identify Lower Quartile: Identify the data set for the lower quartile. For the lower quartile, consider the first half of the data set, excluding the median if necessary. First half is 1, 1, 1, 1, 1. Lower quartile data: 1, 1, 1, 1, 1.Find Lower Quartile Value: Find the value of the lower quartile. Lower quartile data: 1, 1, 1, 1, 1. For an odd number of observations, the median is the middle number. Lower quartile is 1.Identify Upper Quartile: Identify the data set for the upper quartile. For the upper quartile, consider the second half of the data set, excluding the median if necessary. Second half is 3, 3, 3, 4, 6. Upper quartile data: 3, 3, 3, 4, 6.Find Upper Quartile Value: Find the value of the upper quartile. Upper quartile data: 3, 3, 3, 4, 6. For an odd number of observations, the median is the middle number. Upper quartile is 3.Write Quartile Values: Write the values of the lower quartile, median, and the upper quartile. Lower quartile = 1 Median = 2 Upper quartile = 3

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In the data set below, what are the lower quartile, the median, and the upper quartile? $\newline$ $1, 1, 1, 1, 1, 3, 3, 3, 4, 6$ $\newline$ lower quartile $=$ $\_\_$ $\newline$ median $=$ $\_\_$ $\newline$ upper quartile $=$ $\_\_$

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Algebra 1

Calculate quartiles and interquartile range

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Q. In the data set below, what are the lower quartile, the median, and the upper quartile?

\newline

1, 1, 1, 1, 1, 3, 3, 3, 4, 6

\newline

lower quartile

=

\_\_

\newline

median

=

\_\_

\newline

upper quartile

=

\_\_

Arrange and Find Median: Arrange the data set in ascending order and find the median. The data set is already in ascending order: $1, 1, 1, 1, 1, 3, 3, 3, 4, 6$ . Since there are $10$ numbers, the median will be the average of the $5$ th and $6$ th numbers. Median: $(1 + 3) / 2 = 4 / 2 = 2$ .
Identify Lower Quartile: Identify the data set for the lower quartile. $\newline$ For the lower quartile, consider the first half of the data set, excluding the median if necessary. $\newline$ First half is $1, 1, 1, 1, 1$ . $\newline$ Lower quartile data: $1, 1, 1, 1, 1$ .
Find Lower Quartile Value: Find the value of the lower quartile. $\newline$ Lower quartile data: $1, 1, 1, 1, 1$ . $\newline$ For an odd number of observations, the median is the middle number. $\newline$ Lower quartile is $1$ .
Identify Upper Quartile: Identify the data set for the upper quartile. $\newline$ For the upper quartile, consider the second half of the data set, excluding the median if necessary. $\newline$ Second half is $3, 3, 3, 4, 6$ . $\newline$ Upper quartile data: $3, 3, 3, 4, 6$ .
Find Upper Quartile Value: Find the value of the upper quartile. $\newline$ Upper quartile data: $3, 3, 3, 4, 6$ . $\newline$ For an odd number of observations, the median is the middle number. $\newline$ Upper quartile is $3$ .
Write Quartile Values: Write the values of the lower quartile, median, and the upper quartile. $\newline$ Lower quartile = $1$ $\newline$ Median = $2$ $\newline$ Upper quartile = $3$