In the data set below, what are the lower quartile, the median, and the upper quartile? 3, 4, 4, 5, 5, 7, 7, 7, 8, 9 lower quartile = _____ median = _____ upper quartile = _____

Identify Median Calculation: Step 1: Identify the median of the data set 3, 4, 4, 5, 5, 7, 7, 7, 8, 9. Since there are 10 data points, the median will be the average of the 5th and 6th values. Calculation: (5 + 7) / 2 = 6.Lower Quartile Determination: Step 2: Determine the lower quartile. Consider the first half of the data set, excluding the median: 3, 4, 4, 5, 5. The lower quartile is the median of these values, which is the 3rd value. Calculation: 4.Upper Quartile Determination: Step 3: Determine the upper quartile. Consider the second half of the data set, excluding the median: 7, 7, 7, 8, 9. The upper quartile is the median of these values, which is the 3rd value. Calculation: 7.

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In the data set below, what are the lower quartile, the median, and the upper quartile? $\newline$ $3, 4, 4, 5, 5, 7, 7, 7, 8, 9$ $\newline$ lower quartile $=$ $\_\_$ $\newline$ median $=$ $\_\_$ $\newline$ upper quartile $=$ $\_\_$

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Math Problems

Algebra 1

Calculate quartiles and interquartile range

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Q. In the data set below, what are the lower quartile, the median, and the upper quartile?

\newline

3, 4, 4, 5, 5, 7, 7, 7, 8, 9

\newline

lower quartile

=

\_\_

\newline

median

=

\_\_

\newline

upper quartile

=

\_\_

Identify Median Calculation: Step $1$ : Identify the median of the data set $3, 4, 4, 5, 5, 7, 7, 7, 8, 9$ . Since there are $10$ data points, the median will be the average of the $5$ th and $6$ th values. Calculation: $(5 + 7) / 2 = 6$ .
Lower Quartile Determination: Step $2$ : Determine the lower quartile. $\newline$ Consider the first half of the data set, excluding the median: $3, 4, 4, 5, 5$ . $\newline$ The lower quartile is the median of these values, which is the $3$ rd value. $\newline$ Calculation: $4$ .
Upper Quartile Determination: Step $3$ : Determine the upper quartile. $\newline$ Consider the second half of the data set, excluding the median: $7, 7, 7, 8, 9$ . $\newline$ The upper quartile is the median of these values, which is the $3$ rd value. $\newline$ Calculation: $7$ .