In the data set below, what are the lower quartile, the median, and the upper quartile? 10, 10, 31, 31, 52, 57, 67, 71, 71, 79, 87, 92 lower quartile = _____ median = _____ upper quartile = _____

Identify the median: Step 1: Identify the median of the data set. Data set: 10, 10, 31, 31, 52, 57, 67, 71, 71, 79, 87, 92. Since there are 12 numbers, the median will be the average of the 6th and 7th numbers. Calculation: (57 + 67) / 2 = 62.Identify the lower quartile: Step 2: Identify the lower quartile. For the lower quartile, consider the first half of the data set: 10, 10, 31, 31, 52, 57. Since there are 6 numbers, the lower quartile will be the average of the 3rd and 4th numbers. Calculation: (31 + 31) / 2 = 31.Identify the upper quartile: Step 3: Identify the upper quartile. For the upper quartile, consider the second half of the data set: 67, 71, 71, 79, 87, 92. Since there are 6 numbers, the upper quartile will be the average of the 3rd and 4th numbers. Calculation: (71 + 71) / 2 = 71.

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In the data set below, what are the lower quartile, the median, and the upper quartile? $\newline$ $10, 10, 31, 31, 52, 57, 67, 71, 71, 79, 87, 92$ $\newline$ lower quartile $=$ $\_\_$ $\newline$ median $=$ $\_\_$ $\newline$ upper quartile $=$ $\_\_$

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Math Problems

Algebra 1

Calculate quartiles and interquartile range

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Q. In the data set below, what are the lower quartile, the median, and the upper quartile?

\newline

10, 10, 31, 31, 52, 57, 67, 71, 71, 79, 87, 92

\newline

lower quartile

=

\_\_

\newline

median

=

\_\_

\newline

upper quartile

=

\_\_

Identify the median: Step $1$ : Identify the median of the data set. $\newline$ Data set: $10, 10, 31, 31, 52, 57, 67, 71, 71, 79, 87, 92$ . $\newline$ Since there are $12$ numbers, the median will be the average of the $6$ th and $7$ th numbers. $\newline$ Calculation: $(57 + 67) / 2 = 62$ .
Identify the lower quartile: Step $2$ : Identify the lower quartile. $\newline$ For the lower quartile, consider the first half of the data set: $10, 10, 31, 31, 52, 57$ . $\newline$ Since there are $6$ numbers, the lower quartile will be the average of the $3$ rd and $4$ th numbers. $\newline$ Calculation: $(31 + 31) / 2 = 31$ .
Identify the upper quartile: Step $3$ : Identify the upper quartile. $\newline$ For the upper quartile, consider the second half of the data set: $67, 71, 71, 79, 87, 92$ . $\newline$ Since there are $6$ numbers, the upper quartile will be the average of the $3$ rd and $4$ th numbers. $\newline$ Calculation: $(71 + 71) / 2 = 71$ .