In the data set below, what are the lower quartile, the median, and the upper quartile? 26, 31, 45, 65, 72, 73 lower quartile = _____ median = _____ upper quartile = _____

Identify Median Calculation: Step 1: Identify the median of the data set 26, 31, 45, 65, 72, 73. Since there are 6 numbers, the median will be the average of the 3rd and 4th numbers. Calculation: (45 + 65) / 2 = 110 / 2 = 55.Lower Quartile Data Set: Step 2: Identify the data set for the lower quartile. The lower quartile will be the median of the first half of the data set (26, 31, 45). Calculation: The middle number is 31.Upper Quartile Data Set: Step 3: Identify the data set for the upper quartile. The upper quartile will be the median of the second half of the data set (65, 72, 73). Calculation: The middle number is 72.

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In the data set below, what are the lower quartile, the median, and the upper quartile? $\newline$ $26, 31, 45, 65, 72, 73$ $\newline$ lower quartile $=$ $\_\_\_\_$ $\newline$ median $=$ $\_\_\_\_$ $\newline$ upper quartile $=$ $\_\_\_\_$

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Math Problems

Algebra 1

Calculate quartiles and interquartile range

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Q. In the data set below, what are the lower quartile, the median, and the upper quartile?

\newline

26, 31, 45, 65, 72, 73

\newline

lower quartile

=

\_\_\_\_

\newline

median

=

\_\_\_\_

\newline

upper quartile

=

\_\_\_\_

Identify Median Calculation: Step $1$ : Identify the median of the data set $26, 31, 45, 65, 72, 73$ . Since there are $6$ numbers, the median will be the average of the $3$ rd and $4$ th numbers. Calculation: $(45 + 65) / 2 = 110 / 2 = 55$ .
Lower Quartile Data Set: Step $2$ : Identify the data set for the lower quartile. $\newline$ The lower quartile will be the median of the first half of the data set $(26, 31, 45)$ . $\newline$ Calculation: The middle number is $31$ .
Upper Quartile Data Set: Step $3$ : Identify the data set for the upper quartile. $\newline$ The upper quartile will be the median of the second half of the data set $(65, 72, 73)$ . $\newline$ Calculation: The middle number is $72$ .