In the data set below, what are the lower quartile, the median, and the upper quartile? 53, 64, 67, 91, 96, 99 lower quartile = _____ median = _____ upper quartile = _____

Identify Median Calculation: Step 1: Identify the median of the data set 53, 64, 67, 91, 96, 99. Since there are 6 numbers, the median will be the average of the 3rd and 4th numbers. Calculation: (67 + 91) / 2 = 158 / 2 = 79.Lower Quartile Data Set: Step 2: Identify the data set for the lower quartile. For the lower quartile, consider the first half of the data set: 53, 64, 67. Calculation: Median of 53, 64, 67 is 64 (as it is the middle number).Upper Quartile Data Set: Step 3: Identify the data set for the upper quartile. For the upper quartile, consider the second half of the data set: 91, 96, 99. Calculation: Median of 91, 96, 99 is 96 (as it is the middle number).

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In the data set below, what are the lower quartile, the median, and the upper quartile? $\newline$ $53, 64, 67, 91, 96, 99$ $\newline$ lower quartile $=$ $\_\_\_\_$ $\newline$ median $=$ $\_\_\_\_$ $\newline$ upper quartile $=$ $\_\_\_\_$

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Math Problems

Algebra 1

Calculate quartiles and interquartile range

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Q. In the data set below, what are the lower quartile, the median, and the upper quartile?

\newline

53, 64, 67, 91, 96, 99

\newline

lower quartile

=

\_\_\_\_

\newline

median

=

\_\_\_\_

\newline

upper quartile

=

\_\_\_\_

Identify Median Calculation: Step $1$ : Identify the median of the data set $53, 64, 67, 91, 96, 99$ . Since there are $6$ numbers, the median will be the average of the $3$ rd and $4$ th numbers. Calculation: $(67 + 91) / 2 = 158 / 2 = 79$ .
Lower Quartile Data Set: Step $2$ : Identify the data set for the lower quartile. $\newline$ For the lower quartile, consider the first half of the data set: $53$ , $64$ , $67$ . $\newline$ Calculation: Median of $53$ , $64$ , $67$ is $64$ (as it is the middle number).
Upper Quartile Data Set: Step $3$ : Identify the data set for the upper quartile. $\newline$ For the upper quartile, consider the second half of the data set: $91$ , $96$ , $99$ . $\newline$ Calculation: Median of $91$ , $96$ , $99$ is $96$ (as it is the middle number).