In the data set below, what are the lower quartile, the median, and the upper quartile? 1, 1, 2, 7, 9 lower quartile = _____ median = _____ upper quartile = _____

Identify Median: Step 1: Identify the median of the data set 1, 1, 2, 7, 9. Since there are 5 numbers, the median is the middle number. Calculation: The third number is 2. Median = 2 Identify Lower Quartile: Step 2: Identify the lower quartile of the data set. For the lower quartile, consider the first half of the data set, excluding the median. First half is 1, 1. Calculation: The median of 1, 1 is 1. Lower quartile = 1 Identify Upper Quartile: Step 3: Identify the upper quartile of the data set. For the upper quartile, consider the second half of the data set, excluding the median. Second half is 7, 9. Calculation: The median of 7, 9 is 7. Upper quartile = 7

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In the data set below, what are the lower quartile, the median, and the upper quartile? $\newline$ $1, 1, 2, 7, 9$ $\newline$ lower quartile $=$ $\_\_$ $\newline$ median $=$ $\_\_$ $\newline$ upper quartile $=$ $\_\_$

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Math Problems

Algebra 1

Calculate quartiles and interquartile range

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Q. In the data set below, what are the lower quartile, the median, and the upper quartile?

\newline

1, 1, 2, 7, 9

\newline

lower quartile

=

\_\_

\newline

median

=

\_\_

\newline

upper quartile

=

\_\_

Identify Median: Step $1$ : Identify the median of the data set $1, 1, 2, 7, 9$ . Since there are $5$ numbers, the median is the middle number. Calculation: The third number is $2$ . Median $= 2$
Identify Lower Quartile: Step $2$ : Identify the lower quartile of the data set. $\newline$ For the lower quartile, consider the first half of the data set, excluding the median. $\newline$ First half is $1, 1$ . $\newline$ Calculation: The median of $1, 1$ is $1$ . $\newline$ Lower quartile $= 1$
Identify Upper Quartile: Step $3$ : Identify the upper quartile of the data set. $\newline$ For the upper quartile, consider the second half of the data set, excluding the median. $\newline$ Second half is $7, 9$ . $\newline$ Calculation: The median of $7, 9$ is $7$ . $\newline$ Upper quartile = $7$