In the data set below, what are the lower quartile, the median, and the upper quartile? 10, 11, 16, 16, 40, 48, 59, 59, 68, 92 lower quartile = _____ median = _____ upper quartile = _____

Identify the median: Step 1: Identify the median of the data set. Data set: 10, 11, 16, 16, 40, 48, 59, 59, 68, 92. Since there are 10 numbers, the median will be the average of the 5th and 6th numbers. Calculation: (40 + 48) / 2 = 44.Identify the lower quartile: Step 2: Identify the lower quartile. For the lower quartile, consider the first half of the data set, excluding the median. First half: 10, 11, 16, 16, 40. The lower quartile is the median of this subset. Calculation: The third number is 16.Identify the upper quartile: Step 3: Identify the upper quartile. For the upper quartile, consider the second half of the data set, excluding the median. Second half: 48, 59, 59, 68, 92. The upper quartile is the median of this subset. Calculation: The third number is 59.

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In the data set below, what are the lower quartile, the median, and the upper quartile? $\newline$ $10, 11, 16, 16, 40, 48, 59, 59, 68, 92$ $\newline$ lower quartile $=$ $\_\_$ $\newline$ median $=$ $\_\_$ $\newline$ upper quartile $=$ $\_\_$

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Math Problems

Algebra 1

Calculate quartiles and interquartile range

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Q. In the data set below, what are the lower quartile, the median, and the upper quartile?

\newline

10, 11, 16, 16, 40, 48, 59, 59, 68, 92

\newline

lower quartile

=

\_\_

\newline

median

=

\_\_

\newline

upper quartile

=

\_\_

Identify the median: Step $1$ : Identify the median of the data set. $\newline$ Data set: $10, 11, 16, 16, 40, 48, 59, 59, 68, 92$ . $\newline$ Since there are $10$ numbers, the median will be the average of the $5$ th and $6$ th numbers. $\newline$ Calculation: $(40 + 48) / 2 = 44$ .
Identify the lower quartile: Step $2$ : Identify the lower quartile. $\newline$ For the lower quartile, consider the first half of the data set, excluding the median. $\newline$ First half: $10, 11, 16, 16, 40$ . $\newline$ The lower quartile is the median of this subset. $\newline$ Calculation: The third number is $16$ .
Identify the upper quartile: Step $3$ : Identify the upper quartile. $\newline$ For the upper quartile, consider the second half of the data set, excluding the median. $\newline$ Second half: $48, 59, 59, 68, 92$ . $\newline$ The upper quartile is the median of this subset. $\newline$ Calculation: The third number is $59$ .