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In a lab experiment, 70 bacteria are placed in a petri dish. The conditions are such that the number of bacteria is able to double every 15 hours. How many bacteria would there be after 29 hours, to the nearest whole number?
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In a lab experiment, 7070 bacteria are placed in a petri dish. The conditions are such that the number of bacteria is able to double every 1515 hours. How many bacteria would there be after 2929 hours, to the nearest whole number?\newlineAnswer:

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Q. In a lab experiment, 7070 bacteria are placed in a petri dish. The conditions are such that the number of bacteria is able to double every 1515 hours. How many bacteria would there be after 2929 hours, to the nearest whole number?\newlineAnswer:
  1. Determine Doubling Periods: First, we need to determine how many times the bacteria population can double in 2929 hours. Since the bacteria double every 1515 hours, we divide the total time by the doubling period.\newline2929 hours ÷\div 1515 hours per doubling period = 1.93331.9333 doubling periods.
  2. Calculate Full Periods: Since the bacteria can only double an integer number of times, we need to consider how many full doubling periods occur within 2929 hours. We can't have a fraction of a doubling period, so we take the floor of the previous result.\newlineFull doubling periods = 11 (since 1.93331.9333 indicates that only one full doubling period has occurred within 2929 hours).
  3. Calculate After 11 Period: Now we calculate the number of bacteria after one full doubling period. We start with 7070 bacteria and double it once.\newlineNumber of bacteria after 11 doubling period = 70×21=70×2=14070 \times 2^1 = 70 \times 2 = 140 bacteria.
  4. Estimate Growth: We have 1414 hours remaining after the first doubling period (2929 hours - 1515 hours = 1414 hours). We need to estimate the growth during this period. Since the bacteria double every 1515 hours, we can use the fraction of the doubling period that has passed (1415\frac{14}{15}) to estimate the growth.\newlineFraction of doubling period passed = 1415\frac{14}{15}.
  5. Calculate Growth Factor: We calculate the growth factor for the remaining 1414 hours using the fraction of the doubling period.\newlineGrowth factor for 1414 hours = 2(14/15)2^{(14/15)}.
  6. Apply Growth Factor: Now we apply the growth factor to the number of bacteria after the first doubling period to estimate the total number of bacteria after 2929 hours.\newlineEstimated number of bacteria after 2929 hours =140×21415= 140 \times 2^{\frac{14}{15}}.
  7. Calculate Estimated Bacteria: We perform the calculation for the growth factor and then multiply by the number of bacteria after the first doubling period.\newline214151.8972^{\frac{14}{15}} \approx 1.897 (rounded to three decimal places for simplicity).\newlineEstimated number of bacteria after 2929 hours 140×1.897\approx 140 \times 1.897.
  8. Round to Nearest Whole: Finally, we calculate the estimated number of bacteria to the nearest whole number.\newlineEstimated number of bacteria after 2929 hours 140×1.897265.58\approx 140 \times 1.897 \approx 265.58.\newlineSince we need to report the number of bacteria to the nearest whole number, we round 265.58265.58 to 266266.

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