In a lab experiment, 400 bacteria are placed in a petri dish. The conditions are such that the number of bacteria is able to double every 28 hours. How many bacteria would there be after 30 hours, to the nearest whole number? Answer:

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Identify initial number: Identify the initial number of bacteria and the rate at which they double. Initial number of bacteria: 400 Doubling time: 28 hours We need to calculate the number of times the bacteria will double in 30 hours.Calculate doubling periods: Calculate the number of doubling periods in 30 hours. Since the bacteria double every 28 hours, we divide the total time by the doubling time to find the number of doubling periods. Number of doubling periods = Total time / Doubling time Number of doubling periods = 30 hours / 28 hours Number of doubling periods ≈ 1.0714 This is not a whole number because the bacteria do not have enough time to double twice.Calculate number after 30 hours: Calculate the number of bacteria after 30 hours. Since the bacteria double 1.0714 times, we need to multiply the initial number of bacteria by 2 raised to the power of the number of doubling periods. Number of bacteria after 30 hours = Initial number of bacteria * (2 ^ Number of doubling periods) Number of bacteria after 30 hours = 400 * (2 ^ 1.0714) Number of bacteria after 30 hours ≈ 400 * 2.1487 Number of bacteria after 30 hours ≈ 860

In a lab experiment, $400$ bacteria are placed in a petri dish. The conditions are such that the number of bacteria is able to double every $28$ hours. How many bacteria would there be after $30$ hours, to the nearest whole number? $\newline$ Answer:

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In a lab experiment, $400$ bacteria are placed in a petri dish. The conditions are such that the number of bacteria is able to double every $28$ hours. How many bacteria would there be after $30$ hours, to the nearest whole number? $\newline$ Answer: