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In a lab experiment, 40 bacteria are placed in a petri dish. The conditions are such that the number of bacteria is able to double every 28 hours. How many bacteria would there be after 10 hours, to the nearest whole number?
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In a lab experiment, 4040 bacteria are placed in a petri dish. The conditions are such that the number of bacteria is able to double every 2828 hours. How many bacteria would there be after 1010 hours, to the nearest whole number?\newlineAnswer:

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Q. In a lab experiment, 4040 bacteria are placed in a petri dish. The conditions are such that the number of bacteria is able to double every 2828 hours. How many bacteria would there be after 1010 hours, to the nearest whole number?\newlineAnswer:
  1. Understand and Identify: Understand the problem and determine what is given and what needs to be found.\newlineWe know:\newlineInitial number of bacteria: 4040\newlineDoubling time: 2828 hours\newlineTime elapsed: 1010 hours\newlineWe need to find the number of bacteria after 1010 hours.
  2. Calculate Doubling Periods: Calculate the number of times the bacteria population will double in 1010 hours.\newlineSince the bacteria double every 2828 hours, we need to find out how many 2828-hour periods fit into 1010 hours. However, since 1010 hours is less than 2828 hours, the bacteria will not have doubled even once in that time frame.
  3. Determine Growth Rate: Determine the growth rate per hour.\newlineTo find the growth rate per hour, we assume exponential growth and use the formula for exponential growth: N=N0ektN = N_0 \cdot e^{kt}, where NN is the final amount, N0N_0 is the initial amount, kk is the growth rate, and tt is the time in hours. Since we don't have a full doubling period, we need to solve for kk using the doubling time.\newlineDoubling formula: N=N02tTN = N_0 \cdot 2^{\frac{t}{T}}, where TT is the doubling time.\newline2=ek282 = e^{k\cdot 28}\newlinek=ln(2)28k = \frac{\ln(2)}{28}
  4. Calculate Growth Rate: Calculate the growth rate kk.\newlinek=ln(2)28k = \frac{\ln(2)}{28}\newlinek0.0248k \approx 0.0248 (rounded to four decimal places)
  5. Use Growth Rate: Use the growth rate to calculate the number of bacteria after 1010 hours.\newlineN=40×e(0.0248×10)N = 40 \times e^{(0.0248\times10)}\newlineN40×e(0.248)N \approx 40 \times e^{(0.248)}
  6. Evaluate Expression: Evaluate the expression to find the final number of bacteria.\newlineN40×e0.248N \approx 40 \times e^{0.248}\newlineN40×1.282N \approx 40 \times 1.282 (using a calculator for e0.248e^{0.248})\newlineN51.28N \approx 51.28
  7. Round Final Result: Round the number of bacteria to the nearest whole number.\newlineThe number of bacteria after 1010 hours, rounded to the nearest whole number, is approximately 5151.

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