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The average monthly temperature changes from month to month. Suppose that, for a given city, we can model the average temperature in a month with the following function.\newlinef(t)=6027sin(π6t)f(t)=60-27 \sin\left(\frac{\pi}{6}t\right)\newlineIn this equation, f(t)f(t) is the average temperature in a month in degrees Fahrenheit, and tt is the month of the year (January=1=1, February =2,=2,\dots). Find the following. If necessary, round to the nearest hundredth.\newlineTime for one full cycle of ff: \square months\newlineNumber of cycles offf per month: \square\newlineMinimum average temperature in a month: \square

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Q. The average monthly temperature changes from month to month. Suppose that, for a given city, we can model the average temperature in a month with the following function.\newlinef(t)=6027sin(π6t)f(t)=60-27 \sin\left(\frac{\pi}{6}t\right)\newlineIn this equation, f(t)f(t) is the average temperature in a month in degrees Fahrenheit, and tt is the month of the year (January=1=1, February =2,=2,\dots). Find the following. If necessary, round to the nearest hundredth.\newlineTime for one full cycle of ff: \square months\newlineNumber of cycles offf per month: \square\newlineMinimum average temperature in a month: \square
  1. Period of Sine Function: To find the time for one full cycle of ff, we need to determine the period of the sine function. The period of a sine function is given by 2πB\frac{2\pi}{B}, where BB is the coefficient of tt inside the sine function.
  2. Calculate Period: In the function f(t)=6027sin(π6t)f(t)=60-27 \sin\left(\frac{\pi}{6}t\right), the coefficient of tt is π6\frac{\pi}{6}. So, the period is 2π(π6)=2π×(6π)=12\frac{2\pi}{\left(\frac{\pi}{6}\right)} = 2\pi \times \left(\frac{6}{\pi}\right) = 12.
  3. Time for One Cycle: The time for one full cycle of ff is 1212 months.
  4. Cycles per Month: To find the number of cycles of ff per month, we take the reciprocal of the period. Since the period is 1212 months, the number of cycles per month is 112\frac{1}{12}.
  5. Minimum Average Temperature: The minimum average temperature occurs at the lowest point of the sine function, which is when the sine function is at its minimum value of 1-1.
  6. Minimum Value Calculation: The minimum value of the function f(t)f(t) is therefore 6027×(1)=60+27=8760 - 27 \times (-1) = 60 + 27 = 87.

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