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Let’s check out your problem:
if
g
(
x
)
=
2
x
2
+
x
g(x)=2x^2+x
g
(
x
)
=
2
x
2
+
x
what is the value of
g
(
1
2
)
g(\frac{1}{2})
g
(
2
1
)
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Math Problems
Calculus
Find derivatives of exponential functions
Full solution
Q.
if
g
(
x
)
=
2
x
2
+
x
g(x)=2x^2+x
g
(
x
)
=
2
x
2
+
x
what is the value of
g
(
1
2
)
g(\frac{1}{2})
g
(
2
1
)
Substitute
x
=
1
2
x = \frac{1}{2}
x
=
2
1
:
Substitute
x
=
1
2
x = \frac{1}{2}
x
=
2
1
into the function
g
(
x
)
=
2
x
2
+
x
g(x) = 2x^2 + x
g
(
x
)
=
2
x
2
+
x
.
g
(
1
2
)
=
2
(
1
2
)
2
+
(
1
2
)
g\left(\frac{1}{2}\right) = 2\left(\frac{1}{2}\right)^2 + \left(\frac{1}{2}\right)
g
(
2
1
)
=
2
(
2
1
)
2
+
(
2
1
)
Calculate square of
1
2
\frac{1}{2}
2
1
:
Calculate the square of
1
2
\frac{1}{2}
2
1
.
(
1
2
)
2
=
1
4
\left(\frac{1}{2}\right)^2 = \frac{1}{4}
(
2
1
)
2
=
4
1
Multiply by
2
2
2
:
Multiply
2
2
2
by the result from Step
2
2
2
.
\newline
2
×
(
1
4
)
=
1
2
2 \times \left(\frac{1}{4}\right) = \frac{1}{2}
2
×
(
4
1
)
=
2
1
Add to
1
2
\frac{1}{2}
2
1
:
Add the result from Step
3
3
3
to
1
2
\frac{1}{2}
2
1
.
1
2
+
1
2
=
1
\frac{1}{2} + \frac{1}{2} = 1
2
1
+
2
1
=
1
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