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If 2a=2572^a=\sqrt[7]{2^5}, what is the value of aa?

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Q. If 2a=2572^a=\sqrt[7]{2^5}, what is the value of aa?
  1. Identify Given Equation: Identify the given equation and the goal.\newlineWe are given that 2a=2572^a = \sqrt[7]{2^5}, and we need to find the value of aa.
  2. Express Seventh Root: Express the seventh root as an exponent.\newlineThe seventh root of 252^5 can be written as (25)17(2^5)^{\frac{1}{7}}.
  3. Apply Power Rule: Apply the power rule for exponents, which states that (am)n=amn(a^m)^n = a^{m*n}.\newlineSo, (25)1/7(2^5)^{1/7} becomes 25(1/7)2^{5*(1/7)}.
  4. Multiply Exponents: Multiply the exponents to simplify the expression. \newline5×(17)=575 \times \left(\frac{1}{7}\right) = \frac{5}{7}.\newlineSo, 25×(17)2^{5\times\left(\frac{1}{7}\right)} simplifies to 2572^{\frac{5}{7}}.
  5. Set Equal to 2a2^a: Set the simplified expression equal to 2a2^a. We have 2a=25/72^a = 2^{5/7}.
  6. Determine Value of aa: Since the bases are the same, the exponents must be equal.\newlineTherefore, a=57a = \frac{5}{7}.

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