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If
(2,58) and
(9,72) are two anchor points on a trend line, then find the equation of the line.

If $(2,58)$ and $(9,72)$ are two anchor points on a trend line, then find the equation of the line.

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Find the magnitude of a three-dimensional vector

Full solution

Q. If

(2,58)

and

(9,72)

are two anchor points on a trend line, then find the equation of the line.

Calculate Slope: To find the equation of the line, we first need to calculate the slope $m$ of the line using the formula $m = \frac{y_2 - y_1}{x_2 - x_1}$ , where $(x_1, y_1)$ and $(x_2, y_2)$ are the coordinates of the two given points.
Slope Formula: Using the points $(2,58)$ and $(9,72)$ , we plug them into the slope formula: $m = \frac{72 - 58}{9 - 2}$ .
Calculate Slope Value: Calculating the slope, we get $m = \frac{14}{7} = 2$ .
Point-Slope Form: Now that we have the slope, we can use the point-slope form of the equation of a line, which is $y - y_1 = m(x - x_1)$ , where $m$ is the slope and $(x_1, y_1)$ is a point on the line.
Use Given Point: We can use either of the given points for $(x_1, y_1)$ . Let's use the point $(2,58)$ . Plugging the slope and this point into the point-slope form, we get $y - 58 = 2(x - 2)$ .
Slope-Intercept Form: To find the equation in slope-intercept form $y = mx + b$ , we simplify the equation: $y - 58 = 2x - 4$ .
Solve for y: Adding $58$ to both sides of the equation to solve for y, we get $y = 2x + 54$ .

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