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Write the equation of the line that passes through the points 
(-1,-4) and 
(6,-8). Put your answer in fully simplified point-slope form, unless it is a vertical or horizontal line.
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Write the equation of the line that passes through the points (1,4) (-1,-4) and (6,8) (6,-8) . Put your answer in fully simplified point-slope form, unless it is a vertical or horizontal line.\newlineAnswer:\newlineSubmit Answer

Full solution

Q. Write the equation of the line that passes through the points (1,4) (-1,-4) and (6,8) (6,-8) . Put your answer in fully simplified point-slope form, unless it is a vertical or horizontal line.\newlineAnswer:\newlineSubmit Answer
  1. Calculate the Slope: First, calculate the slope mm of the line using the formula m=y2y1x2x1m = \frac{y_2 - y_1}{x_2 - x_1}, where (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2) are the given points.\newlinem=8(4)6(1)m = \frac{-8 - (-4)}{6 - (-1)}\newlinem=8+46+1m = \frac{-8 + 4}{6 + 1}\newlinem=47m = \frac{-4}{7}
  2. Use Point-Slope Form: Now that we have the slope, we can use the point-slope form of the line equation, which is yy1=m(xx1)y - y_1 = m(x - x_1). We can use either of the given points; let's use the first point (1,4)(-1, -4). \newliney(4)=47(x(1))y - (-4) = \frac{-4}{7}(x - (-1))\newliney+4=47(x+1)y + 4 = \frac{-4}{7}(x + 1)
  3. Simplify the Equation: Next, we simplify the equation.\newliney+4=(47)x(47)(1)y + 4 = \left(-\frac{4}{7}\right)x - \left(\frac{4}{7}\right)(1)\newliney+4=(47)x47y + 4 = \left(-\frac{4}{7}\right)x - \frac{4}{7}
  4. Subtract to Simplify: To get the equation in point-slope form, we subtract 44 from both sides.\newliney=(47)x474y = \left(-\frac{4}{7}\right)x - \frac{4}{7} - 4\newliney=(47)x47287y = \left(-\frac{4}{7}\right)x - \frac{4}{7} - \frac{28}{7}\newliney=(47)x327y = \left(-\frac{4}{7}\right)x - \frac{32}{7}
  5. Final Equation: The equation is now in point-slope form, and it is fully simplified.

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