How many solutions does this equation have? –h + 10 = –h Choices: (A)no solution (B)one solution (C)infinitely many solutions

Analyze the equation: Analyze the equation –h + 10 = –h. We want to find out if there are any values of h that make this equation true.Isolate the variable h: Attempt to isolate the variable h on one side of the equation. Subtract –h from both sides of the equation to see if we can simplify it. (–h + 10) - (–h) = (–h) - (–h)Simplify the equation: Simplify both sides of the equation. On the left side, –h and +h cancel each other out, leaving us with 10. On the right side, –h and +h also cancel each other out, leaving us with 0. So, we have 10 = 0.Determine if equation makes sense: Determine if the simplified equation makes sense. 10 = 0 is not true for any value of h, which means there is no value of h that can satisfy the equation –h + 10 = –h.

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How many solutions does this equation have? $\newline$ $-h + 10 = -h$ $\newline$ Choices: $\newline$ (A)no solution $\newline$ (B)one solution $\newline$ (C)infinitely many solutions

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Math Problems

Algebra 1

Find the number of solutions to a linear equation

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Q. How many solutions does this equation have?

\newline

-h + 10 = -h

\newline

Choices:

\newline

(A)no solution

\newline

(B)one solution

\newline

(C)infinitely many solutions

Analyze the equation: Analyze the equation $–h + 10 = –h$ . We want to find out if there are any values of $h$ that make this equation true.
Isolate the variable $h$ : Attempt to isolate the variable $h$ on one side of the equation. $\newline$ Subtract $–h$ from both sides of the equation to see if we can simplify it. $\newline$ $(–h + 10) - (–h) = (–h) - (–h)$
Simplify the equation: Simplify both sides of the equation. $\newline$ On the left side, $-h$ and $+h$ cancel each other out, leaving us with $10$ . $\newline$ On the right side, $-h$ and $+h$ also cancel each other out, leaving us with $0$ . $\newline$ So, we have $10 = 0$ .
Determine if equation makes sense: Determine if the simplified equation makes sense. $\newline$ $10 = 0$ is not true for any value of $h$ , which means there is no value of $h$ that can satisfy the equation $–h + 10 = –h$ .