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How many solutions does this equation have?\newline6q=7q36q = 7q - 3\newlineChoices:\newline(A)no solution\newline(B)one solution\newline(C)infinitely many solutions

Full solution

Q. How many solutions does this equation have?\newline6q=7q36q = 7q - 3\newlineChoices:\newline(A)no solution\newline(B)one solution\newline(C)infinitely many solutions
  1. Subtract 7q7q: Subtract 7q7q from both sides of the equation to isolate the variable on one side.\newline6q7q=7q7q36q - 7q = 7q - 7q - 3\newline=q=3= -q = -3
  2. Divide by 1-1: Divide both sides by 1-1 to solve for q.\newlineq/1=3/1-q / -1 = -3 / -1\newlineq=3q = 3
  3. Check solution: Check the solution by substituting q=3q = 3 back into the original equation.6(3)=7(3)36(3) = 7(3) - 318=21318 = 21 - 318=1818 = 18Since the left side equals the right side, the solution q=3q = 3 is correct.

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