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How many solutions does this equation have?\newline−4f+10=−4f-4f + 10 = -4f\newlineChoices:\newline(A) no solution\newline(B) one solution\newline(C) infinitely many solutions

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Q. How many solutions does this equation have?\newline−4f+10=−4f-4f + 10 = -4f\newlineChoices:\newline(A) no solution\newline(B) one solution\newline(C) infinitely many solutions
  1. Simplify equation: Simplify the equation by subtracting –4f–4f from both sides to isolate the constant terms.–4f+10−(–4f)=–4f−(–4f)–4f + 10 - (–4f) = –4f - (–4f)10=010 = 0

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