How many solutions does this equation have? –2s = –s − 6 Choices: (A)no solution (B)one solution (C)infinitely many solutions

Add s to both sides: Add s to both sides of the equation to isolate terms with the variable on one side. –2s + s = –s + s − 6 This simplifies to: –s = –6Multiply by -1: Multiply both sides of the equation by -1 to solve for s. –1 * (–s) = –1 * (–6) This simplifies to: s = 6Check the solution: Check the solution by substituting s = 6 back into the original equation. –2(6) = –(6) − 6 –12 = –6 − 6 –12 = –12 Since the left side equals the right side, the solution s = 6 is correct.

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How many solutions does this equation have? $\newline$ $-2s = -s - 6$ $\newline$ Choices: $\newline$ (A)no solution $\newline$ (B)one solution $\newline$ (C)infinitely many solutions

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Math Problems

Algebra 1

Find the number of solutions to a linear equation

Full solution

Q. How many solutions does this equation have?

\newline

-2s = -s - 6

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Choices:

\newline

(A)no solution

\newline

(B)one solution

\newline

(C)infinitely many solutions

Add $s$ to both sides: Add $s$ to both sides of the equation to isolate terms with the variable on one side. $\newline$ $-2s + s = -s + s - 6$ $\newline$ This simplifies to: $\newline$ $-s = -6$
Multiply by $-1$ : Multiply both sides of the equation by $-1$ to solve for $s$ . $\newline$ $-1 \times (\text{-}s) = -1 \times (\text{-}6)$ $\newline$ This simplifies to: $\newline$ $s = 6$
Check the solution: Check the solution by substituting $s = 6$ back into the original equation. $\newline$ $-2(6) = -(6) - 6$ $\newline$ $-12 = -6 - 6$ $\newline$ $-12 = -12$ $\newline$ Since the left side equals the right side, the solution $s = 6$ is correct.