How does h(x)=4^x change over the interval from x=8 to x=10? Choices:[[h(x) increases by a factor of 16]\n[h(x) increases by a factor of 8]\n[h(x) decreases by a factor of 16]\n[h(x) decreases by a factor of 8%]]

Find h(8): Find h(8). h(8) = 4^8 = 65536Find h(10): Find h(10). h(10) = 4^10 = 1048576Calculate factor increase: Calculate the factor by which h(x) increases. Factor = h(10) / h(8) = 1048576 / 65536 = 16

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How does $h(x)=4^x$ change over the interval from $x=8$ to $x=10$ ? $\newline$ Choices: $\newline$ $\text{h(x) increases by a factor of 16}$ $\newline$ $\text{h(x) increases by a factor of 8}$ $\newline$ $\text{h(x) decreases by a factor of 16}$ $\newline$ $\text{h(x) decreases by a factor of 8\%}$

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Math Problems

Grade 8

Solve equations with variable exponents

Full solution

Q. How does

h(x)=4^x

change over the interval from

x=8

x=10

\newline

Choices:

\newline

\text{h(x) increases by a factor of 16}

\newline

\text{h(x) increases by a factor of 8}

\newline

\text{h(x) decreases by a factor of 16}

\newline

\text{h(x) decreases by a factor of 8\%}

Find $h(8)$ : Find $h(8)$ . $\newline$ $h(8) = 4^8$ $\newline$ $= 65536$
Find $h(10)$ : Find $h(10)$ . $h(10) = 4^{10}$ = $1048576$
Calculate factor increase: Calculate the factor by which $h(x)$ increases. Factor = $\frac{h(10)}{h(8)}$ = $\frac{1048576}{65536}$ = $16$