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How does f(y)=−4y+5f(y) = -4y + 5 change over the interval from y=1y = 1 to y=3y = 3 ?\newlinef(y)f(y) decreases by a factor of 22\newlinef(y)f(y) decreases by 88\newlinef(y)f(y) decreases by 1212\newlinef(y)f(y) decreases by 22

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Add and subtract integers: word problemsright chevron icon

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Q. How does f(y)=−4y+5f(y) = -4y + 5 change over the interval from y=1y = 1 to y=3y = 3 ?\newlinef(y)f(y) decreases by a factor of 22\newlinef(y)f(y) decreases by 88\newlinef(y)f(y) decreases by 1212\newlinef(y)f(y) decreases by 22
  1. Calculate f(1)f(1): Calculate f(1)f(1).\newlinef(1)=−4(1)+5=−4+5=1f(1) = -4(1) + 5 = -4 + 5 = 1
  2. Calculate f(3)f(3): Calculate f(3)f(3). f(3)=−4(3)+5=−12+5=−7f(3) = -4(3) + 5 = -12 + 5 = -7
  3. Find change in f(y)f(y): Find the change in f(y)f(y) from y=1y=1 to y=3y=3. Change = f(3)−f(1)=−7−1=−8f(3) - f(1) = -7 - 1 = -8

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