Hiroki and Mapiya were asked to find an explicit formula for the sequence 125,25,5,1,…, where the first term should be f(1).Hiroki said the formula is f(n)=625⋅(51)n, andMapiya said the formula is f(n)=125⋅(51)n.Which one of them is right?Choose 1 answer:(A) Only Hiroki(B) Only Mapiya(C) Both Hiroki and Mapiya(D) Neither Hiroki nor Mapiya
Q. Hiroki and Mapiya were asked to find an explicit formula for the sequence 125,25,5,1,…, where the first term should be f(1).Hiroki said the formula is f(n)=625⋅(51)n, andMapiya said the formula is f(n)=125⋅(51)n.Which one of them is right?Choose 1 answer:(A) Only Hiroki(B) Only Mapiya(C) Both Hiroki and Mapiya(D) Neither Hiroki nor Mapiya
Check Hiroki's Formula: To determine the correct formula, we need to check if each formula correctly calculates the terms of the sequence when n is substituted with the term number.
Test Hiroki's Formula: Let's test Hiroki's formula: f(n)=625×(51)n. We will substitute n=1 to see if we get the first term of the sequence, which is 125.f(1)=625×(51)1=625×51=125.This matches the first term of the sequence.
Test Mapiya's Formula: Now let's test Mapiya's formula: f(n)=125×(51)n. We will also substitute n=1 to see if we get the first term of the sequence.f(1)=125×(51)1=125×51=25.This does not match the first term of the sequence; it matches the second term instead.
Conclusion: Since Hiroki's formula correctly produced the first term of the sequence when n=1, and Mapiya's formula did not, we can conclude that only Hiroki's formula is correct.
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