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Here are yesterday's high temperatures (in degrees Fahrenheit) in 1212 U.S. cities.\newline53,54,57,59,60,61,61,72,72,73,80,8353,54,57,59,60,61,61,72,72,73,80,83\newlineNotice that the temperatures are ordered from least to greatest.\newlineGive the median, lower quartile, and upper quartile for the data set.\newline(a) Median:\newline(b) Lower quartile:\newline(c) Upper quartile:

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Q. Here are yesterday's high temperatures (in degrees Fahrenheit) in 1212 U.S. cities.\newline53,54,57,59,60,61,61,72,72,73,80,8353,54,57,59,60,61,61,72,72,73,80,83\newlineNotice that the temperatures are ordered from least to greatest.\newlineGive the median, lower quartile, and upper quartile for the data set.\newline(a) Median:\newline(b) Lower quartile:\newline(c) Upper quartile:
  1. Identify the median: Identify the median of the data set.\newlineThe data set is already ordered from least to greatest: 53,54,57,59,60,61,61,72,72,73,80,8353, 54, 57, 59, 60, 61, 61, 72, 72, 73, 80, 83.\newlineSince there are 1212 numbers, the median will be the average of the 66th and 77th numbers.\newline66th number: 6161\newline77th number: 6161\newlineAverage: (61+61)/2=61(61 + 61) / 2 = 61\newlineMedian: 6161
  2. Identify lower quartile data: Identify the data set for the lower quartile.\newlineFor the lower quartile, consider the first half of the data set, excluding the median if it's a single number.\newlineSince we have an even number of observations, we will take the first 66 numbers: 5353, 5454, 5757, 5959, 6060, 6161.\newlineLower quartile data: 5353, 5454, 5757, 5959, 6060, 6161
  3. Find lower quartile value: Find the value of the lower quartile.\newlineLower quartile data: 53,54,57,59,60,6153, 54, 57, 59, 60, 61\newlineFor an even number of observations, the lower quartile is the average of the 33rd and 44th numbers.\newline33rd number: 5757\newline44th number: 5959\newlineAverage: (57+59)/2=58(57 + 59) / 2 = 58\newlineLower quartile: 5858
  4. Identify upper quartile data: Identify the data set for the upper quartile.\newlineFor the upper quartile, consider the second half of the data set, excluding the median if it's a single number.\newlineSince we have an even number of observations, we will take the last 66 numbers: 6161, 7272, 7272, 7373, 8080, 8383.\newlineUpper quartile data: 6161, 7272, 7272, 7373, 8080, 8383
  5. Find upper quartile value: Find the value of the upper quartile.\newlineUpper quartile data: 61,72,72,73,80,8361, 72, 72, 73, 80, 83\newlineFor an even number of observations, the upper quartile is the average of the 33rd and 44th numbers.\newline33rd number: 7272\newline44th number: 7373\newlineAverage: (72+73)/2=72.5(72 + 73) / 2 = 72.5\newlineUpper quartile: 72.572.5

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