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Harper uploaded a funny video of her dog onto a website.
The relationship between the elapsed time, 
d, in days, since the video was first uploaded, and the total number of views, 
V(d), that the video received is modeled by the following function.

V(d)=4^(1.25 d)
How many views will the video receive after 6 days?
Round your answer, if necessary, to the nearest hundredth.

◻ views

Harper uploaded a funny video of her dog onto a website.\newlineThe relationship between the elapsed time, d d , in days, since the video was first uploaded, and the total number of views, V(d) V(d) , that the video received is modeled by the following function.\newlineV(d)=41.25d V(d)=4^{1.25 d} \newlineHow many views will the video receive after 66 days?\newlineRound your answer, if necessary, to the nearest hundredth.\newline \square views

Full solution

Q. Harper uploaded a funny video of her dog onto a website.\newlineThe relationship between the elapsed time, d d , in days, since the video was first uploaded, and the total number of views, V(d) V(d) , that the video received is modeled by the following function.\newlineV(d)=41.25d V(d)=4^{1.25 d} \newlineHow many views will the video receive after 66 days?\newlineRound your answer, if necessary, to the nearest hundredth.\newline \square views
  1. Identify Function and Value: Identify the given function and the value to be substituted.\newlineWe are given the function V(d)=4(1.25d)V(d) = 4^{(1.25d)}, where dd is the number of days since the video was uploaded. We need to find the number of views after 66 days, so we will substitute dd with 66.
  2. Substitute Value into Function: Substitute the value of dd into the function.\newlineV(6)=41.25×6V(6) = 4^{1.25 \times 6}\newlineNow we need to calculate 1.25×61.25 \times 6.\newline1.25×6=7.51.25 \times 6 = 7.5\newlineSo, V(6)=47.5V(6) = 4^{7.5}
  3. Calculate Exponential Value: Calculate the value of 44 raised to the power of 7.57.5. Using a calculator, we find that 47.54^{7.5} is approximately 23708.6423708.64.
  4. Round to Nearest Hundredth: Round the answer to the nearest hundredth, if necessary.\newlineThe value 23708.6423708.64 is already to the nearest hundredth, so no further rounding is needed.

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