h(n)=-10+12 n Complete the recursive formula of h(n). {:[h(1)=◻],[h(n)=h(n-1)+]:}

Determine first term: Determine the first term of the sequence h(n). To find h(1), we substitute n = 1 into the formula h(n) = -10 + 12n. h(1) = -10 + 12(1) = -10 + 12 = 2Find common difference: Find the difference between consecutive terms to identify the common difference. To find the common difference, we can calculate h(2) - h(1). h(2) = -10 + 12(2) = -10 + 24 = 14 The common difference is h(2) - h(1) = 14 - 2 = 12.Write recursive formula: Write the recursive formula using the first term and the common difference. The recursive formula for an arithmetic sequence is h(n) = h(n-1) + d, where d is the common difference. Since we have found that h(1) = 2 and the common difference d = 12, the recursive formula is: h(n) = h(n-1) + 12

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Find derivatives of sine and cosine functions

Full solution

h(n)=-10+12n

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Complete the recursive formula of

h(n)

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h(1)=\square

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h(n)=h(n-1)+\square

Determine first term: Determine the first term of the sequence $h(n)$ . $\newline$ To find $h(1)$ , we substitute $n = 1$ into the formula $h(n) = -10 + 12n$ . $\newline$ $h(1) = -10 + 12(1) = -10 + 12 = 2$
Find common difference: Find the difference between consecutive terms to identify the common difference. $\newline$ To find the common difference, we can calculate $h(2) - h(1)$ . $\newline$ $h(2) = -10 + 12(2) = -10 + 24 = 14$ $\newline$ The common difference is $h(2) - h(1) = 14 - 2 = 12$ .
Write recursive formula: Write the recursive formula using the first term and the common difference. $\newline$ The recursive formula for an arithmetic sequence is $h(n) = h(n-1) + d$ , where $d$ is the common difference. $\newline$ Since we have found that $h(1) = 2$ and the common difference $d = 12$ , the recursive formula is: $\newline$ $h(n) = h(n-1) + 12$