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h=11.2-0.125 d
The ceiling height, 
h, in feet, for a particular room in a house a distance of 
d feet from the west wall is given by the equation. In order for the ceiling height to decrease by 1 foot, how much does the distance from the west wall change in feet?
Choose 1 answer:
(A) 0.125
(B) 8
(C) 
11.2
(D) 89.6

h=11.20.125dh=11.2-0.125d\newlineThe ceiling height, hh, in feet, for a particular room in a house a distance of dd feet from the west wall is given by the equation. In order for the ceiling height to decrease by 11 foot, how much does the distance from the west wall change in feet?\newlineChoose 11 answer:\newline(A) 0.1250.125\newline(B) 88\newline(C) 11.211.2\newline(D) 89.689.6

Full solution

Q. h=11.20.125dh=11.2-0.125d\newlineThe ceiling height, hh, in feet, for a particular room in a house a distance of dd feet from the west wall is given by the equation. In order for the ceiling height to decrease by 11 foot, how much does the distance from the west wall change in feet?\newlineChoose 11 answer:\newline(A) 0.1250.125\newline(B) 88\newline(C) 11.211.2\newline(D) 89.689.6
  1. Given Equation: We are given the equation h=11.20.125dh = 11.2 - 0.125d, where hh is the ceiling height in feet and dd is the distance from the west wall in feet. We want to find out how much dd needs to change for hh to decrease by 11 foot.
  2. Denote Initial Heights: Let's denote the initial height as h1h_1 and the height after the decrease as h2h_2. We know that h2=h11h_2 = h_1 - 1 because the height decreases by 11 foot.
  3. Denote Initial Distances: Let's denote the initial distance from the west wall as d1d_1 and the distance after the change as d2d_2. We need to find the change in distance, which is d2d1d_2 - d_1.
  4. Express Heights in Terms: Using the given equation, we can express h1h_1 and h2h_2 in terms of d1d_1 and d2d_2 respectively:\newlineh1=11.20.125d1h_1 = 11.2 - 0.125d_1\newlineh2=11.20.125d2h_2 = 11.2 - 0.125d_2
  5. Substitute Expressions: Since h2=h11h_2 = h_1 - 1, we can substitute the expressions for h1h_1 and h2h_2: \newline11.20.125d2=(11.20.125d1)111.2 - 0.125d_2 = (11.2 - 0.125d_1) - 1
  6. Simplify Equation: Simplify the equation by distributing the negative sign and combining like terms: 11.20.125d2=11.20.125d1111.2 - 0.125d^2 = 11.2 - 0.125d^1 - 1
  7. Subtract Constant Term: Subtract 11.211.2 from both sides to get rid of the constant term:\newline0.125d2=0.125d11-0.125d^2 = -0.125d^1 - 1
  8. Solve for Change in Distance: Now, we can divide both sides by 0.125-0.125 to solve for d2d1d_2 - d_1:d2d1=10.125d_2 - d_1 = \frac{-1}{-0.125}
  9. Calculate Change in Distance: Calculate the change in distance: \newlined2d1=10.125d_2 - d_1 = \frac{1}{0.125}\newlined2d1=8d_2 - d_1 = 8

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