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Given 
x > 0 and 
y > 0, select the expression that is equivalent to

root(3)(-125x^(3)y^(5))

-5xy^((5)/(3))

-5x^(9)y^(15)

5ixy^((5)/(3))

5ix^(9)y^(15)

Given x>0 and y>0 , select the expression that is equivalent to\newline125x3y53 \sqrt[3]{-125 x^{3} y^{5}} \newline5xy53 -5 x y^{\frac{5}{3}} \newline5x9y15 -5 x^{9} y^{15} \newline5ixy53 5 i x y^{\frac{5}{3}} \newline5ix9y15 5 i x^{9} y^{15}

Full solution

Q. Given x>0 x>0 and y>0 y>0 , select the expression that is equivalent to\newline125x3y53 \sqrt[3]{-125 x^{3} y^{5}} \newline5xy53 -5 x y^{\frac{5}{3}} \newline5x9y15 -5 x^{9} y^{15} \newline5ixy53 5 i x y^{\frac{5}{3}} \newline5ix9y15 5 i x^{9} y^{15}
  1. Simplify Constant Term: Simplify the cube root of the constant term.\newlineThe cube root of 125-125 is 5-5 because (5)3=125(-5)^3 = -125.
  2. Simplify Variable Term x3x^{3}: Simplify the cube root of the variable term x3x^{3}. The cube root of x3x^{3} is xx because x(3/3)=x1=xx^{(3/3)} = x^{1} = x.
  3. Simplify Variable Term y5y^{5}: Simplify the cube root of the variable term y5y^{5}. Since the exponent 55 is not a multiple of 33, we cannot take the cube root of y5y^{5} directly. Instead, we express y5y^{5} as y3×y2y^{3} \times y^{2} and take the cube root of y3y^{3}, which is yy. The remaining y2y^{2} stays inside the cube root.
  4. Combine Results: Combine the results from Steps 11, 22, and 33. Combining the cube roots of the constant and variable terms, we get 5xy-5xy times the cube root of y2y^{2}, which can be written as y2/3y^{2/3}.
  5. Write Final Expression: Write the final expression.\newlineThe final expression is 5xy×y2/3-5xy \times y^{2/3}, which simplifies to 5xy1+2/3=5xy5/3-5xy^{1 + 2/3} = -5xy^{5/3}.

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