Q. Given the function y=(−8x−10)(−6x3−8−7x−1), find dxdy in any form.Answer: dxdy=
Apply Product Rule: To find the derivative of the given function, we will use the product rule, which states that the derivative of a product of two functions is the derivative of the first function times the second function plus the first function times the derivative of the second function.
Find Derivatives: Let's denote the first function as f(x)=−8x−10 and the second function as g(x)=−6x3−8−7x−1. We will first find the derivatives f′(x) and g′(x).
Calculate f′(x): The derivative of f(x)=−8x−10 with respect to x is f′(x)=−8, since the derivative of a constant is 0 and the derivative of −8x with respect to x is −8.
Calculate g′(x): The derivative of g(x)=−6x3−8−7x−1 with respect to x is g′(x)=−18x2+7x−2. This is because the derivative of −6x3 is −18x2, the derivative of −8 is 0, and the derivative of −7x−1 is 7x−2.
Use Product Rule: Now we apply the product rule: (dxdy)=f′(x)g(x)+f(x)g′(x).
Substitute Expressions: Substitute the expressions for f′(x), g(x), f(x), and g′(x) into the product rule formula: dxdy=(−8)(−6x3−8−7x−1)+(−8x−10)(−18x2+7x−2).
Simplify Expression: Now we simplify the expression: (dxdy=48x3+64+56x−1−144x3−80x2−56x−70x−2).
Combine Like Terms: Combine like terms to get the final derivative: (dy)/(dx)=(48x3−144x3)+(−80x2)+(56x−1−56x)+(64−70x−2).
Final Derivative: Simplify the expression further: (dxdy)=−96x3−80x2−56x+56x−1+64−70x−2.
Simplify Further: The final simplified form of the derivative is: (dy)/(dx)=−96x3−80x2−56x+x56+64−x270.
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