Q. Given the function y=−2(−5x2−2x)3, find dxdy in any form.Answer: dxdy=
Apply Chain Rule: First, we need to apply the chain rule to differentiate the function y=−2(−5x2−2x)3 with respect to x. The chain rule states that the derivative of a composite function is the derivative of the outer function evaluated at the inner function times the derivative of the inner function.
Identify Functions: Let's identify the outer function and the inner function. The outer function is u3 (where u is some function of x), and the inner function is u=−5x2−2x. We will first differentiate the outer function with respect to u, which gives us 3u2.
Differentiate Outer Function: Now we differentiate the inner function u=−5x2−2x with respect to x. The derivative of −5x2 with respect to x is −10x, and the derivative of −2x with respect to x is −2. So the derivative of the inner function is dxdu=−10x−2.
Differentiate Inner Function: Next, we apply the chain rule by multiplying the derivative of the outer function with respect to u (which is 3u2) by the derivative of the inner function with respect to x (which is −10x−2). This gives us (dy/dx)=3u2∗(−10x−2).
Apply Chain Rule Multiplication: Substitute the inner function u back into the expression for u2 to get (3(−5x2−2x)2)∗(−10x−2).
Substitute Inner Function: Finally, we need to multiply the constant factor −2 from the original function y=−2(−5x2−2x)3 by the derivative we found. This gives us (dy/dx)=−2×(3(−5x2−2x)2)×(−10x−2).
Multiply by Constant Factor: Simplify the expression to get the final derivative. (dxdy)=−2×3×(−10x−2)×(−5x2−2x)2=−6×(−10x−2)×(−5x2−2x)2.
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