For the function f(x)=x^(5)-10, find f^(-1)(x). f^(-1)(x)=(x+10)^(5) f^(-1)(x)=root(5)(x-10) f^(-1)(x)=root(5)(x+10) f^(-1)(x)=x^(5)+10

Replace with y: To find the inverse function, we first replace f(x) with y: y = x^5 - 10Add 10: Next, we solve for x in terms of y to find the inverse function. We start by adding 10 to both sides of the equation: y + 10 = x^5Take fifth root: Now, we take the fifth root of both sides to solve for x: x = (y + 10)^(1/5)Express as inverse function: We then replace x with f^(-1)(x) and y with x to express the inverse function: f^(-1)(x) = (x + 10)^(1/5)

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For the function
f(x)=x^(5)-10, find
f^(-1)(x).

f^(-1)(x)=(x+10)^(5)

f^(-1)(x)=root(5)(x-10)

f^(-1)(x)=root(5)(x+10)

f^(-1)(x)=x^(5)+10

For the function $f(x)=x^{5}-10$ , find $f^{-1}(x)$ . $\newline$ $f^{-1}(x)=(x+10)^{5}$ $\newline$ $f^{-1}(x)=\sqrt[5]{x-10}$ $\newline$ $f^{-1}(x)=\sqrt[5]{x+10}$ $\newline$ $f^{-1}(x)=x^{5}+10$

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Q. For the function

f(x)=x^{5}-10

, find

f^{-1}(x)

\newline

f^{-1}(x)=(x+10)^{5}

\newline

f^{-1}(x)=\sqrt[5]{x-10}

\newline

f^{-1}(x)=\sqrt[5]{x+10}

\newline

f^{-1}(x)=x^{5}+10

Replace with $y$ : To find the inverse function, we first replace $f(x)$ with $y$ : $y = x^5 - 10$
Add $10$ : Next, we solve for $x$ in terms of $y$ to find the inverse function. We start by adding $10$ to both sides of the equation: $\newline$ $y + 10 = x^5$
Take fifth root: Now, we take the fifth root of both sides to solve for $x$ : $x = (y + 10)^{\frac{1}{5}}$
Express as inverse function: We then replace $x$ with $f^{-1}(x)$ and $y$ with $x$ to express the inverse function: $f^{-1}(x) = (x + 10)^{\frac{1}{5}}$