For the function f(x)=(9-2x)/(3+4x), find f^(-1)(x). Answer: f^(-1)(x)=

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For the function  f(x)=(9-2x)/(3+4x), find  f^(-1)(x). Answer:  f^(-1)(x)=

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Replace with y: To find the inverse function, f^(-1)(x), we need to switch the roles of x and y in the original function and then solve for y. Let's start by replacing f(x) with y to make it easier to work with. y = (9 - 2x) / (3 + 4x)Interchange x and y: Now, interchange x and y to find the inverse function. x = (9 - 2y) / (3 + 4y)Multiply both sides: Next, we need to solve for y. To do this, we'll multiply both sides of the equation by (3 + 4y) to eliminate the denominator. x(3 + 4y) = 9 - 2yDistribute x: Distribute x on the left side of the equation. 3x + 4xy = 9 - 2yMove terms with y: Now, we want to get all the terms with y on one side and the constant terms on the other side. Let's move the terms involving y to the left side and the constant terms to the right side. 4xy + 2y = 9 - 3xFactor out y: Factor out y from the left side of the equation. y(4x + 2) = 9 - 3xDivide both sides: Divide both sides by (4x + 2) to solve for y. y = (9 - 3x) / (4x + 2)Write inverse function: Now that we have solved for y, we can write the inverse function. Replace y with f^(-1)(x) to denote the inverse function. f^(-1)(x) = (9 - 3x) / (4x + 2)

For the function $f(x)=\frac{9-2 x}{3+4 x}$ , find $f^{-1}(x)$ . $\newline$ Answer: $f^{-1}(x)=$

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For the function f(x)=9−2x3+4x f(x)=\frac{9-2 x}{3+4 x} f(x)=3+4x9−2x​, find f−1(x) f^{-1}(x) f−1(x).\newlineAnswer: f−1(x)= f^{-1}(x)= f−1(x)=

For the function $f(x)=\frac{9-2 x}{3+4 x}$ , find $f^{-1}(x)$ . $\newline$ Answer: $f^{-1}(x)=$