Q. For the following quadratic equation, find the discriminant.−6x2+53x−180=−3x2−7xAnswer:
Simplify the Equation: First, we need to simplify the given equation by moving all terms to one side to get a standard quadratic equation of the form ax2+bx+c=0. −6x2+53x−180=−3x2−7x Add 3x2 to both sides: −6x2+3x2+53x−180=−7x Combine like terms: −3x2+53x−180=−7x Now, add 7x to both sides: −3x2+53x+7x−180=0 Combine like terms: −3x2+60x−180=0
Find the Discriminant: Now that we have the quadratic equation in standard form, we can find the discriminant using the formula b2−4ac, where a, b, and c are the coefficients from the quadratic equation ax2+bx+c=0. For our equation, a=−3, b=60, and c=−180. Let's calculate the discriminant: Discriminant = b2−4ac Discriminant = (60)2−4(−3)(−180)
Calculate the Discriminant: Perform the calculations:Discriminant = 3600−4(−3)(−180)Discriminant = 3600−4(540)Discriminant = 3600−2160Discriminant = 1440
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