For a high school dinner function for teachers and students, the math department bought 6 cases of juice and 1 case of bottled water for a total of $135. The science department bought 4 cases of juice and 2 cases of bottled water for a total of $110. How much did a case of juice cost?Choose 1 answer:(A) $12.50(B) $15.00(C) $20.00(D) $25.00
Q. For a high school dinner function for teachers and students, the math department bought 6 cases of juice and 1 case of bottled water for a total of $135. The science department bought 4 cases of juice and 2 cases of bottled water for a total of $110. How much did a case of juice cost?Choose 1 answer:(A) $12.50(B) $15.00(C) $20.00(D) $25.00
Define Variables: Let's call the cost of a case of juice J and the cost of a case of bottled water W. We have two equations based on the problem.1) 6J+1W=1352) 4J+2W=110
Modify Second Equation: First, we can multiply the second equation by 21 to make it easier to eliminate W.So, 2J+W=55
Eliminate W: Now, we subtract the modified second equation from the first equation to eliminate W.(6J+1W)−(2J+W)=135−55This simplifies to 4J=80
Solve for J: Solving for J, we divide both sides by 4.J=480J=20
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