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Find the
y-coordinate of the
y-intercept of the polynomial function defined below.

f(x)=8x^(3)-8-8x-6x^(2)
Answer:

Find the $y$ -coordinate of the $y$ -intercept of the polynomial function defined below. $\newline$ $f(x)=8 x^{3}-8-8 x-6 x^{2}$ $\newline$ Answer:

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Find derivatives of sine and cosine functions

Full solution

Q. Find the

y

-coordinate of the

y

-intercept of the polynomial function defined below.

\newline

f(x)=8 x^{3}-8-8 x-6 x^{2}

\newline

Answer:

Evaluate at $x=0$ : To find the $y$ -coordinate of the $y$ -intercept of the function $f(x)$ , we need to evaluate $f(x)$ at $x = 0$ , because the $y$ -intercept occurs where the graph of the function crosses the $y$ -axis, and the $x$ -coordinate of any point on the $y$ -axis is $y$ $0$ .
Substitute $x=0$ : Substitute $x = 0$ into the polynomial function $f(x) = 8x^3 - 8 - 8x - 6x^2$ . $\newline$ $f(0) = 8(0)^3 - 8 - 8(0) - 6(0)^2$
Simplify expression: Simplify the expression by calculating the value of each term with $x = 0$ . $\newline$ $f(0) = 8(0) - 8 - 8(0) - 6(0)$ $\newline$ $f(0) = 0 - 8 - 0 - 0$
Combine terms: Combine the terms to find the $y$ -coordinate of the $y$ -intercept. $f(0) = -8$

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